(3x^-3/2)+(6x^1/2)

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Solution for (3x^-3/2)+(6x^1/2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(6*x^1)/2+(3*x^-3)/2 = 0

(6*x)/2+(3*x^-3)/2 = 0

3*x+3/2*x^-3 = 0

3*x*(1/2*x^-4+1) = 0

1/2*x^-4 = -1 // : 1/2

x^-4 = -2

-4 < 0

1/(x^4) = -2 // * x^4

1 = -2*x^4 // : -2

-1/2 = x^4

3*x = 0

3*x = 0 // : 3

x = 0

x in { 0} 

x belongs to the empty set

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